Please need help in these 3 algebra questions !!!!7. Add: (3s2 + 7s + 2) + (5s2 + 9s – 1) A. 8s2 + 16s + 3 B. 8s4 + 16s + 1 C. 8s2 + 16s + 1D. –2s2 – 2s + 18. (–3t2u3)(5t7u8) = _______. A. –15t14u24 B. 2t9u11 C. –15t–5u–5 D. –15t9u1111. The square of a number is equal to 6 more than the number. Find all such numbers. A. –4; –3 B. –2 C. 3; –2 D. –3

Answer:[tex]\large\boxed{7.\ B.\ 8s^2+16s+1}\\\\\boxed{8.\ D.\ -15t^9u^{11}}\\\\\boxed{11.\ C.\ 3,\ -2}[/tex]Step-by-step explanation:[tex]7.\\(3s^2+7s+2)+(5s^2+9s-1)=3s^2+7s+2+5s^2+9s-1\\\\\text{combine like terms}\\\\=(3s^2+5s^2)+(7s+9s)+(2-1)\\\\=8s^2+16s+1[/tex][tex]8.\\(-3t^2u^3)(5t^7u^8)=(-3\cdot5)(t^2t^7)(u^3u^8)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=-15t^{2+7}u^{3+8}=-15t^9u^{11}[/tex][tex]11.\\n-the\ number\\\\n^2=n+6\qquad\text{subtract}\ n\ \text{and}\ 6\ \text{from both sides}\\\\n^2-n-6=0\\\\n^2+2n-3n-6=0\\\\n(n+2)-3(n+2)=0\\\\(n+2)(n-3)=0\iff n+2=0\ \vee\ n-3=0\\\\n+2=0\qquad\text{subtract 2 from both sides}\\n=-2\\\\n-3=0\qquad\text{add 3 to both sides}\\n=3[/tex]