A deli ordered 6 1/2 wheels of cheese .Over the weekend 3 5/8 wheels of cheese were sold.On Tuesday another wheels were sold.How much cheese was left for Wednesday

Answer:[tex]1\frac{7}{8}[/tex] wheels of cheese.Step-by-step explanation: We have been given that a deli ordered 6 1/2 wheels of cheese. Over the weekend 3 5/8 wheels of cheese were sold. On Tuesday another wheels were sold.To find the cheese left for Wednesday, we will subtract 3 5/8 and 1 from 6 1/2 as:[tex]\text{Cheese left for Wednesday}=6\frac{1}{2}-3\frac{5}{8}-1[/tex]Convert mixed fraction into improper fraction:[tex]\text{Cheese left for Wednesday}=\frac{2\times 6+1}{2}-\frac{3\times 8+5}{8}-1[/tex][tex]\text{Cheese left for Wednesday}=\frac{13}{2}-\frac{29}{8}-1[/tex]Make a common denominator:[tex]\text{Cheese left for Wednesday}=\frac{13\times 4}{2\times 4}-\frac{29}{8}-\frac{1\times 8}{8}[/tex][tex]\text{Cheese left for Wednesday}=\frac{52}{8}-\frac{29}{8}-\frac{8}{8}[/tex]Combine numerators:[tex]\text{Cheese left for Wednesday}=\frac{52-29-8}{8}[/tex][tex]\text{Cheese left for Wednesday}=\frac{15}{8}[/tex][tex]\text{Cheese left for Wednesday}=1\frac{7}{8}[/tex]Therefore, [tex]1\frac{7}{8}[/tex] wheels of cheese was left for Wednesday.